36x^2+9x-1600=0

Solution for 36x^2+9x-1600=0 equation:

36x^2+9x-1600=0

a = 36; b = 9; c = -1600;
Δ = b2-4ac
Δ = 92-4·36·(-1600)
Δ = 230481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{230481}=\sqrt{9*25609}=\sqrt{9}*\sqrt{25609}=3\sqrt{25609}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{25609}}{2*36}=\frac{-9-3\sqrt{25609}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{25609}}{2*36}=\frac{-9+3\sqrt{25609}}{72}
$